Last Index of Number Coding ninjas Solutions

Last Index of Number

Given an array of length N and an integer x, you need to find and return the last index of integer x present in the array. Return -1 if it is not present in the array.

Last index means - if x is present multiple times in the array, return the index at which x comes last in the array.

You should start traversing your array from 0, not from (N - 1).

Do this recursively. Indexing in the array starts from 0.

Input Format :

Line 1 : An Integer N i.e. size of array
Line 2 : N integers which are elements of the array, separated by spaces
Line 3 : Integer x

Output Format :

last index or -1

Constraints :

1 <= N <= 10^3

Sample Input :

4
9 8 10 8
8

Sample Output :

3

Source code:

int lastIndex(int input[], int size, int x) {
  /* Don't write main().
     Don't read input, it is passed as function argument.
     Return output and don't print it.
     Taking input and printing output is handled automatically.
  */



    if(size==0)
        return -1;
    int a=lastIndex(input+1,size-1,x);
      if(a!=-1)
          return a+1;
      if(input[0]==x)
        return 0;
      else
         return -1;
}

Last Index of Number Coding ninjas Solutions