Wipro Questions with solutions LCM and HCF Part - 2

11. There are two numbers, the square of first number is 36 .If the HCF and LCM of two numbers are 6 and 42 respectively,Find the other number?

A: 45

B: 42

C: 43

D: 44


Correct answer: option b

The first number is square root of 36 => 6

Let the other number be x.

As we know that,

Product of two numbers = LCM * HCF

6 * x = 6*42

X= 42



12. Ramya calculated the product of two numbers is 13225 , the hcf is 25. Then find the LCM?

A: 345

B: 279

C: 347

D: 529


Correct answer: option D

13225= 25*LCM

HCF= 529

Correct Answer: option d



13.What is the smallest number which when divided by 13 and 17 leaves a remainder of 8?

A: 248

B: 229

C: 258

D: 274


Let us find the LCM of 13 and 17.

13 = 1*13.

17 = 1*17

LCM= 13*17 =221.

Add 8 to this to get the required answer.

The answer is 229. It gives a remainder of 8 when divided by 13 and 17.



14.If LCM of two prime numbers a and b (a>b) is 437 then the value of 5b-5a is:

A:18

B:-16

C:12

D:-20


If LCM of a and b is 437. Then, ab= 437.

Now, co-primes with product 437 are (1, 437) and (19, 23).

Since a and b are prime numbers and a>b, we have a=23 and b=19.

Therefore, 5b- 5a= 5*19- 5*23 = -20

Correct Answer: Option d



15.The number between 3000 and 4000 which is exactly divisible by 30, 36, and 80 is:

A:3646

B:3647

C:3600

D:3657


Firstly, we find the LCM of 30, 36, and 80 = 720

∴ Required number = Multiple of 720

= 720 × 5 = 3600

because 3000 < 3600 < 4000



16.The reciprocal of the hcf and lcm of two are 1/36 and 1/48 . if one of the number is 24 then other no. is

A:72

B:144

C:96

D:48


reciprocal of the hcf and lcm of two are 1/36 and 1/48

so, HCF = 36 , LCM = 48

LCM * HCF = product of two numbers

48*36 / 24 = 72



17.If the LCM and HCF of 2 numbers are 26 and 23 respectively, the product of 2 numbers can be expressed as

A:23*26

B:14*28

C:23*30

D:25*26


LCM* HCF = product of number

23*26= product

Correct Answer: Option A



18.If LCM and HCF of two numbers are 169 and 26 respectively. Then the smallest factor of the product of the two numbers is

A:5

B:6

C:7

D:2


169*26 = 4394

4394 = 2 * 13 * 13 *13

Hence the smallest factor is 2

Correct Answer: Option d


19.The product of two numbers is 841 and their L.C.M is 29 then HCF is?

A:12

B:18

C:29

D:14


Hcf * LCM = product of two no.

hcf * 29 = 841

hcf = 841/29

hcf = 29 ans




Wipro Questions with solutions LCM and HCF  Part - 2


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