Given three values - Start Fahrenheit Value (S), End Fahrenheit value (E) and Step Size (W), you need to convert all Fahrenheit values from Start to End at the gap of W, into their corresponding Celsius values and print the table.
Input Format :
3 integers - S, E and W respectively
Output Format :
Fahrenheit to Celsius conversion table. One line for every Fahrenheit and Celsius Fahrenheit value. Fahrenheit value and its corresponding Celsius value should be separate by tab ("\t")
Constraints :
0 <= S <= 1000
0 <= E <= 1000
0 <= W <= 1000
Sample Input 1:
0
100
20
Sample Output 1:
0 -17
20 -6
40 4
60 15
80 26
100 37
Sample Input 2:
120
200
40
Sample Output 2:
120 48
160 71
200 93
Explanation for Sample Output 2 :
Start value is 120, end value is 200 and step size is 40. Therefore, the values we need to convert are 120, 120 + 40 = 160, and 160 + 40 = 200.
The formula for converting Fahrenheit to Celsius is:
Celsius Value = (5/9)*(Fahrenheit Value - 32)
Plugging 120 into the formula, the celsius value will be (5 / 9)*(120 - 32) => (5 / 9) * 88 => (5 * 88) / 9 => 440 / 9 => 48.88
But we'll only print 48 because we are only interested in the integral part of the value.
Source Code :
Given three values - Start Fahrenheit Value (S), End Fahrenheit value (E) and Step Size (W), you need to convert all Fahrenheit values from Start to End at the gap of W, into their corresponding Celsius values and print the table.
void printTable(int start, int end, int step) {
{
int s,e,w,i,c;
cin>>start>>end>>step;
for(i=start;i<=end;i=i+step)
{ c=(i-32)*5/9;
cout<<i<<"\t"<<c<<endl;
}
}
}
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